| Author | Message | ||
| rob guess (Beast)
Member Username: Beast Post Number: 297 Registered: 5-2003 |
Robert; you might wat to take a look at this link from the MIT web site. http://web.mit.edu/charvak/Public/torquevspower.html on his main page he also has a few links in about Ferraris. http://web.mit.edu/charvak/www/index.html Looks like the work of a student that has very good taste. Rob | ||
| DGS (Dgs)
Member Username: Dgs Post Number: 302 Registered: 5-2003 |
A "Quarter Horse", of course. ( http://www.q-horse.com/ ) (Ya gotta know these scuderia terms.)  | ||
| Mitch Alsup (Mitch_alsup)
Intermediate Member Username: Mitch_alsup Post Number: 1015 Registered: 4-2002 |
HP(rpm) = TQ(rpm) * rpm / 5252 | ||
| Jim Schad (Jim_schad)
Intermediate Member Username: Jim_schad Post Number: 1816 Registered: 7-2002 |
figures...the link looks to be to University of Arkansas. | ||
| Robert (Rjklein4470)
Member Username: Rjklein4470 Post Number: 293 Registered: 3-2002 |
Thanks Jim Nice work Quah, but what does one leg = | ||
| Lawrence Coppari (Lawrence)
Member Username: Lawrence Post Number: 760 Registered: 4-2002 |
Horsepower is not force times distance. That is work. Power is the rate of doing work so there must be units of time in it. Your equation 1 is misleading. 1 HP = force(lbs) X Distance (ft)/time (sec)/550 so if you exert 550 lbs of force over 1 foot in one second, you have 1 horsepower. | ||
| Steve Magnusson (91tr)
Intermediate Member Username: 91tr Post Number: 2087 Registered: 1-2001 |
I'd like to see the look on the dyno operator's face when you ask him/her how much "force" your engine is making . For rotational machines: (horse)power = torque x RPM x whatever constants you need to make the units work out is the more useful form. (Jim you missed a "divide by 5252" in Eqn. 1 -- but I think Eqn. 1 is missing "the time required to move the distance"? Eqn 2 looks OK though.) | ||
| Quah Trout (Quah)
New member Username: Quah Post Number: 3 Registered: 1-2003 |
# of legs divided by 4 <g> | ||
| Jim Schad (Jim_schad)
Intermediate Member Username: Jim_schad Post Number: 1815 Registered: 7-2002 |
In the United States, the horsepower unit is the commonly used measure of the power output of internal combustion engines and electric motors. By definition, one horsepower is the ability to do 33,000 foot-pounds (ft-lbs) of work in one minute (or 550 ft-lbs of work in one second). The basic horsepower formula is presented below as Equation 1: Equation 1: Horsepower = Force, lbs. X Distance, ft. http://www.uark.edu/depts/aeedhp/agscience/MEASWORK.htm | ||
| Robert (Rjklein4470)
Member Username: Rjklein4470 Post Number: 292 Registered: 3-2002 |
I know that I should know this, but sadly I do not. I understand the theory behind what horse power is, but what is the formula to arrive at what one horse power ='s |