Ok Geniuses: My kids algebra problem. | FerrariChat

Ok Geniuses: My kids algebra problem.

Discussion in 'Other Off Topic Forum' started by jimpo1, Aug 31, 2010.

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  1. jimpo1

    jimpo1 Two Time F1 World Champ Owner Silver Subscribed

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    I quit algebra 30 years ago, I'm no help. He has an answer, we're verifying.

    Here it is:

    2. Given 2 f (x) = 3x^2 + 2x -4 and g(x)= x^2 - 4x +1. John was asked to find ( f + g)(x)
    and he got the answer 4x^3-2x^2-3x . Explain John’s error in complete sentences and
    give the correct answer.

    (That was the problem, not his answer)

    The answer he got was 3x^3-2x-3.
     
  2. thirteendog

    thirteendog Formula 3

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    Gotta know just a little more information. What exactly do the instructions tell him to find? I'm assuming where the lines intersects?
     
  3. jimpo1

    jimpo1 Two Time F1 World Champ Owner Silver Subscribed

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    Those are the complete instructions. He says he needs it to be simplified and that you just need to add them together.
     
  4. thirteendog

    thirteendog Formula 3

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    Cool beans, give me a moment to knock my old brain around and I'll spit out an answer lol
     
  5. Erich

    Erich Formula 3

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    Is this correct? You wrote 2 f(x)=......

    Did you mean f(x)=3x^2+2x-4 ?
     
  6. jimpo1

    jimpo1 Two Time F1 World Champ Owner Silver Subscribed

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    Yes thats correct, sorry.
     
  7. toggie

    toggie F1 World Champ Owner Silver Subscribed

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    I'm thinking the answer is 4x^2 - 2x -3.

    Let me explain why. Suppose x = 3.
    Solve f(x) when x = 3. Then, solve g(x) when x = 3. Add those two answers together.
    Compare that saved answer to solving (f+g)(x) when x = 3 and see if you get the same answer. Note that (f+g)(x) is the formula I provide above.

    So, when x = 3, f(x) = 9 - 12 + 1 = -2. And, when x= 3, g(x) = 27 + 6 - 4 = 29. So, -2 + 29 = 27.
    Now, when x = 3, (f + g)(x) = (4 * 9) - (2 * 3) - 3 = 36 - 6 - 3 = 27.

    This should be true for any value of x.

    So, the way you add any f(x) and g(x) formulas together is you keep each factor (that is, power of x) separate, adding together only "like powers of x".
    In the above example, the x^2 "factor" is 3x^2 in f(x) and 1x^2 in g(x). Added together it is 4x^2.
    And the x^1 "factor" is -4x in f(x) and 2x in g(x). Added together it is -2x.
    And the x^0 "factor" is +1 in f(x) and -4 in g(x). Added together it is -3.
    Putting the three "factor" parts together to make the new formula is 4x^2 - 2x - 3. This is (f+g)(x).
     
    Last edited: Aug 31, 2010
  8. thirteendog

    thirteendog Formula 3

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    I didn't get anything near what your son got
    3x^3 -10x^2 -8x + 1
     
  9. jimpo1

    jimpo1 Two Time F1 World Champ Owner Silver Subscribed

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    Thanks!
     
  10. toggie

    toggie F1 World Champ Owner Silver Subscribed

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    I'm no expert, so please verify with someone who really knows math.

    I am always completely logical and can defend my results - however, that isn't always the correct answer in school. YMMV.
     
  11. ApexOversteer

    ApexOversteer F1 Veteran

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    Sir, this is an English speaking website and I will kindly ask you to refrain from posting in Chinese or Swahili or whatever that is. Thank you.
     
  12. toggie

    toggie F1 World Champ Owner Silver Subscribed

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    Da nada. :)
     
  13. finnerty

    finnerty F1 World Champ

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    Ahhhhh...... pretty difficult to get a cubic (x^3) factor by adding squares (x^2) and linears (x), folks ----- in fact, it is impossible.
     
  14. tundraphile

    tundraphile F1 Veteran

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    If I could add to what has already been posted.

    Basically, (f+g)(x) = f(x) + g(x)

    In this case both of these functions are parabolas. Imagine both of them graphed on the same chart. Each of them for a given x, will have a unique value of y. If you were to add the values of y for any given x you would have the same single value of y if you use the answer provided.
     
  15. Townshend

    Townshend F1 Veteran Owner Rossa Subscribed

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    I'm inclined to agree with toggie
     
  16. Townshend

    Townshend F1 Veteran Owner Rossa Subscribed

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    Correct, that's a better way of looking at it. So essentially..

    (3x² + 2x -4) + (x² - 4x +1)

    3x² - x² + 2x - 4x - 4 + 1

    4x² - 2x - 3
     
    Last edited: Aug 31, 2010
  17. finnerty

    finnerty F1 World Champ

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    That is correct.

    "John's" (the fictitious boy in the original problem definition) mistake was that, for some reason, he has multiplied the correct answer by a factor of "x".

    To clarify, let's call the correct solution h(x). Then, h(x) = 4x^2 - 2x - 3. Multiply h(x) by "x" as John did, and you will have --- 4x^3 - 2x^2 - 3x.

    Isn't mathematics fun :):):)
     
  18. finnerty

    finnerty F1 World Champ

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    And, hey Jim ----

    Quit getting fellow F-chatters to do your son's homework for him!!!!!!

    Just teasing, of course :) ----- happy to help :)
     
  19. finnerty

    finnerty F1 World Champ

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    Ahhhhhhh........ that's "3x^2 (+) x^2....." I believe you made a typo there....
     
  20. Tony G

    Tony G Rookie

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    the correct answer is 4x^2-2x-3

    johns mistake was he multiplied his answer by x

    (f+g)x is a function that adds two individual functions, it doesn't mean f plus g times x
     

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