Here: (clutch/thrust bearing replacement (700 posts) https://www.ferrarichat.com/forum/threads/the-f50-thread.127114/ .
Another celebration of 30 years of the F50. Interesting stories (making an F1 car for the road, variants 333 SP & F50 GT, owner’s views, values, comparison to F40). Image Unavailable, Please Login Get your Octane copy and enjoy…
L. Fox Collection the Linfox-owned Australian Automotive Research Centre in Anglesea. Image Unavailable, Please Login Image Unavailable, Please Login
Is this tire a new design / compound? Will the design (less the 'legacy tour' script) be available to owners who didn't participate in the legacy tour?
From @petite-caprice on Reddit: https://packaged-media.redd.it/vqwwg1vsmf7f1/pb/m2-res_1080p.mp4?m=DASHPlaylist.mpd&v=1&e=1750186800&s=1e80eb5ae011241d421288e7efba9316ab5eda54 Image Unavailable, Please Login Image Unavailable, Please Login Image Unavailable, Please Login Image Unavailable, Please Login
Yes I believe it was commissioned by Ferrari to replace the old Goodyear Fiorano tyres, so owners can continue to use the cars on newer rubber, and those who paid to go on the tour received a set as part of their care package………. I mentioned last year in this thread possibly, about the F50 owners and specialists should club together to do a run of new tyres but someone provided info regarding the new tyre in development More info from Pirelli here. https://press.pirelli.com/with-new-p7-tyres-for-the-gto-pirelli-equips--all-ferrari-supercars/
Hello does anyone know about this Ferrari F50? Someone claimed that the pictures taken in Indonesia in early 2000s. Based on my knowledge there was only 1 F50 (US-Spec) that was in Indonesia and the car was sold to Japan in 1997. Is it posssibly AI too? Thanks Image Unavailable, Please Login Image Unavailable, Please Login Image Unavailable, Please Login Image Unavailable, Please Login
In Brazil, completely restored, the F50 p2-3, one of the three pre-production prototypes. https://www.instagram.com/reel/DLTiDG9sSme/?igsh=MWx6M2RwMDE1aDk4OA==