Brain Teaser!

I don't think you'd have to turn over the 6 because if it's a vowel it follows the rules and if it isn't there wasn't a rule saying that only vowels could have even numbers on the other side. So just three cards need to be turned over.

This is my second choice for an answer.

 

So, OP, are you going to post the "answer" to this Brain Teaser, or admit that it's a load ?

 

Is the answer Blue?

 

I only graduated high school so I dont know!!

 

Please post the teaser exactly as it is printed in the book. The way it's worded in your post is gibberish.

 

Based on the first sentence, the answer is 1. All four cards have the letters and numbers--it doesn't specify that they are different from one another. But if that's the rule, then you shouldn't have to turn any cards over.

 

"...a card with a vowel on it always has an even number on the other side."

My inferences are that:
(1) Any vowel (in this case only the "A") MUST have an even number on the other side (4 or 6).
(2) Any non-vowel (in this case "B", "C", "D") can have either an even OR an odd number on the other side.
(3) Any even number ("2", "4") can have either a vowel or a consonant on the other side.
(4) Any odd number ("3", "5") must NOT have a vowel (in this case only the "A") on the other side.
(5) The cards may be arranged randomly face up, either letters or numbers. <--------- this was NOT explicitly stated-- what did the original problem say?????

The only two conditions are that (i) the A have a 4 or a 6 on the back, and that (ii) the 3 does NOT have the A on the back.

If the "A" card and "4" and "6" are face up, as (A) (B) (4) (6), then you don't need to turn over any cards because the rule is obviously false.

If the "A" card is face up, and 0 or 1 even number card is face up, as (A) (B) (C) (4), then you only need to turn "A" over to verify or disprove the rule.

If, however, the "A" is face down and both even number cards are face up, as (3) (4) (5) (6),
and you turn over the (4) and it is NOT an "A", you have not proven or disproven the rule; you also need to turn over the (6).

Bring on the cats!
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This wording doesn't say that the cards have to have letters on one side and numbers on the other. The conditions for this problem were poorly detailed.

Assuming that each one of those is a different person... The one drinking coke is fine no matter the age. The two who we already know the ages for don't need their IDs checked, of course (though how do we know their ages?). So we just need to check the one who is drinking beer.

 

Thank you... Thats why you would have to look at every card. Who knows whats on the back.